[solution(솔루션)] 기계재료학 (공업재료) 3판(Engineering Materials 1, Ashby 출판사 BH)
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Download : [솔루션] 기계재료학 (공업재료) 3.pdf
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many applications, substitutes are easily found at small penalty of cost. But in
The fraction of material recycled is obviously important. Products may be
and Design, 3rd edn
in cutting tools and lighting (a fluorescent tube contains more tungsten, as
−rA
but development time is again important.
rA
certain specific uses, most elements are not easily replaced. Examples: tungsten
= 100
r
Engineering Materials I
기계, 공학, 과학, 연습문제, 솔루션, 재료
rB
platinum as a catalyst in chemical processing; etc. A long development time
(c) Using the equation of Answer (a) we find that aluminium overtakes steel
순서
An Introduction to Properties, Applications
1
where CA and CB are the current rates of consumption t = t0 and Pt and
2.1. (a) For commodity A Pt = CA exp
Download : [솔루션] 기계재료학 (공업재료) 3.pdf( 21 )
ln 2 ≈ 70
stone or cast-iron in construction; plastics for glass or metals as containers. For
(up to 25 years) may be needed to find a replacement.
다.레포트 > 공학,기술계열
r
100
t
t = 100
설명
in 201 years; polymers overtake steel in 55 years.
(b) The doubling time, tD, is calculated by setting Ct = t = 2C0, giving
a starter filament, than an incandescent bulb!); lead in lead-acid batteries;
Recycling
![[솔루션] 기계재료학 (공업재료) 3-2312_01_.gif](http://www.happyreport.co.kr/prev/201112/%5B%EC%86%94%EB%A3%A8%EC%85%98%5D%20%EA%B8%B0%EA%B3%84%EC%9E%AC%EB%A3%8C%ED%95%99%20(%EA%B3%B5%EC%97%85%EC%9E%AC%EB%A3%8C)%203-2312_01_.gif)
![[솔루션] 기계재료학 (공업재료) 3-2312_02_.gif](http://www.happyreport.co.kr/prev/201112/%5B%EC%86%94%EB%A3%A8%EC%85%98%5D%20%EA%B8%B0%EA%B3%84%EC%9E%AC%EB%A3%8C%ED%95%99%20(%EA%B3%B5%EC%97%85%EC%9E%AC%EB%A3%8C)%203-2312_02_.gif)
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![[솔루션] 기계재료학 (공업재료) 3-2312_04_.gif](http://www.happyreport.co.kr/prev/201112/%5B%EC%86%94%EB%A3%A8%EC%85%98%5D%20%EA%B8%B0%EA%B3%84%EC%9E%AC%EB%A3%8C%ED%95%99%20(%EA%B3%B5%EC%97%85%EC%9E%AC%EB%A3%8C)%203-2312_04_.gif)
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by building large plant (economy of scale); using high-strength materials; use
Substitution of the values given for r in the table into this equation gives the
Qt are the values at t = t . Equating and solving for t gives
Design to use proportionally smaller amounts of scarce materials, for example,
doubling times as 35, 23 and 18 years respectively.
Examples: aluminium for copper as a conductor; reinforced concrete for wood,
[solution(솔루션)] 기계재료학 (공업재료) 3판(Engineering Materials 1, Ashby 출판사 BH)
More Economic Design
Substitution
Solutions to Examples
CA
CB
100
of surface coatings to prevent metal loss by corrosion (e.g. in motor cars).
and for commodity B Qt = CB exp
re-designed to make recycling easier, and new recycling processes developed,
ln
rB
2.2. Principal conservation measures (see Section 2.7):
t
tD
SOLUTIONS MANUAL
2 Solutions Manual: Engineering Materials I
(아래는 해법 표지 부분과 2장의 일부 연습문제 부분입니다.
